kVA is simply kilovolts times amps. It is roughly a synonym for kW, except
that it probably ignores the phase angle. So for resistive loads, kVA == kW
but for inductive or capacitive loads, kVA would be larger.
1 hp == 746 W. But when people talk about phase converter hp limits, they are
looking not just at the steady state load but also at the startup peak current,
which is a fairly substantial multiple of the steady state load.
For your application, you probably have some motor loads and possibly some
others (power supplies). If they are mostly motor loads, use the steady state
kVA spec and convert that back to hp by dividing by 0.746. Alternatively, if
the converter has a rated steady state load, match that against the steady
state power spec for the machine. The peak current handling of the converter
will take care of either motor startup peaks, or power supply inrush current.
paul
> On May 4, 2017, at 10:36 AM, Guy Sotomayor Jr via cctalk
> <[email protected]> wrote:
>
> Does anyone know how to convert KVa to 208v 3-phase currents and/or HP?
> IBM’s docs all specify power in KVa and most of the 3 phase converters (other
> than what Bob posted) seem to specify HP. If I’m going to spend serious coin
> on a phase converter (I think I found it online for ~$3k…ouch!), I want to
> make sure it’s sized properly.
>
> Thanks.
>
> TTFN - Guy
