Danny Backx wrote:
> On Sat, 2006-11-18 at 09:53 +0000, Pedro Alves wrote:
>   
>> Did you ever get to analise this more? Look at the path, and understand why 
>> the i386 as is being called?
>> Looks like something is trying to call the native (i386) as, but it ends up 
>> picking that script on the way.
>> I guess building with CFLAGS=-v would help pin this down.
>>     
>
> Yes I did, that's how I came up with the workaround. And I've looked
> around the net and found confirmation for it.
>
> BTW it's not the i386 as that gets called, it's the other way around:
> the src/build-cegcc/gcc/gcc/as script gets generated somehow in the gcc
> configuration steps, and contains :
>       #!/bin/sh
>       exec /opt/cegcc/bin/arm-wince-cegcc-as "$@"
>
> which causes it to call the new binutils cross-assembler, where it
> should call the native i386 assembler instead.
>
>   
Yes, that's what I meant, the native gcc driver is trying to call the 
native as.

> It happens to do that because . is in my path before system directories;
> this may be why you don't see it :
>       sh-3.00$ findpath as
>       as :./as  /usr/bin/as   
>       sh-3.00$ pwd
>
> (findpath is a script of my own that does something similar to
> "whereis".)
>
>   
Huh!? I've asked about your PATH settings before, precisely because I 
thought you had something like this.
If you have '.' on the PATH, you are supposed to have it *last*'. All 
hell breaks lose if you don't, you get what you deserve. :)

http://www.faqs.org/faqs/unix-faq/faq/part2/section-13.html

Why do you need it? Can you consider changing it and reverting the hack?

Cheers,
Pedro Alves



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