Hi ,
I was going through this simplified crush algorithm given in ceph website.
def crush(pg):
all_osds = ['osd.0', 'osd.1', 'osd.2', ...]
result = []
# size is the number of copies; primary+replicas
while len(result) < size:
--> *r = hash(pg)*
chosen = all_osds[ r % len(all_osds) ]
if chosen in result:
# OSD can be picked only once
continue
result.append(chosen)
return result
10:24 PM (51 minutes ago)
In the line where *r = hash(pg)* , will it gives the same hash value in
every iteration ?
if that is the case we always endup choosing the same osd from the list
or will the pg number be used as seed for the hashing so that r value
changes in the next iteration.
Am I missing something really basic ??
Can somebody please provide me some pointers ?
--
Thanks,
Shylesh Kumar M
_______________________________________________
ceph-users mailing list
ceph-users@lists.ceph.com
http://lists.ceph.com/listinfo.cgi/ceph-users-ceph.com
