Eric Dumazet <[email protected]> writes: > I guess so. It must travel through the old_flows list from the tail to > the head (so each flows in old_flows must be serviced by one quantum), > to get the right to be declared as 'empty' and gain the honor to get > promoted to 'new_flows' next time a packet is enqueued. > > If all flows are slow, but the queue can still build up, because there > are too many flows for the possible bandwidth, than all flows are > actually considered as thick, as if we had a single RR queue. (the > old_flows).
Right, that makes sense. Everything is relative. Thanks for clearing things up! :) -Toke -- Toke Høiland-Jørgensen [email protected]
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