Double-checking, I formally apologize for my hasty reply.
The proper equation is the one given below.
Sharon
(skulking away, promising not to shoot from the hip before coffee has taken
affect.)
At 09:59 AM 3/15/2001 -0500, Mark Wimer wrote:
>
>Sharon, longitude lines surely change more than a mile between the equator
>and Alaska, no?
>Hmph. I'm learning a lot here.
>Now I'd like to see an equation that converts UTM to decimal degrees....
>
>
>Mark
>[EMAIL PROTECTED]
>
>
>
>I usually use haversine's formula to calculate the distance between two
>points (based on lat.-long. coords.):
>
><CFSET distance =
>#Evaluate(((pi()*3969.96)/180)*(ACos((Sin(lat_A)*Sin(lat_B)) +
>(Cos(lat_A)*Cos(lat_B)*Cos(lon_A-lon_B)))))#>
>
> ~Simon
>
>-----Original Message-----
>From: Sharon DiOrio [mailto:[EMAIL PROTECTED]]
>Sent: Thursday, March 15, 2001 9:34 AM
>To: CF-Community
>Subject: Re: longtitude and latitude
>
>
>It can be done. In fact, if you're only measuring Longitude, it's a simple
>matter of multiplying the difference between the two numbers times the
>constant 111.3 (the number of miles in a degree). (Keep in mind that the
>constant actually varies from 110.57 to 111.32 as the latitude gets closer
>to the equator. You can probably find some kind of table on the web for
>exact constants.)
>
>If you're dealing with longitude *and* latitude, then you'll need to think
>back to the Pythagorean Theorum (A^2 * B^2 = C^2) to triangulate distances
>returned in degrees, which you can then mulitiply by the constant.
>
>(I finally figured out when I'd use that High School math again...)
>
>Sharon
>
>At 12:07 PM 3/15/2001 +0000, John McCosker wrote:
>>Maybe, or maybe not, a cf question but I feel the audience is of the right
>>kaliber of intelligence to be asking anyway!!
>>
>>I'm working with Longtitude and latitude co-ordinates at the moment,
>>
>>what I would like to do is work out the differnce in Kilometers (or miles)
>>between two references i.e.
>>
>>Lontitude 5.48084768538759 and longtitude -5.9417692388158496
>>
>>I am pulling both co-ordinates from a cfquery and then setting a zoom
>level
>>with a centre point depending on the distance between the two points.
>>
>>Any help on this matter would be appreciated....
>>
>>Thank you
>>
>>JMC
>>
>>
>
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