I'll play you a game of chess anytime you'd like.... I'm an avid player.
Actually, the equation is quite different when duplicates are not
allowed...I wish I could remember the formula.  It's something like (60 * 59
* 58 * 57 * 56 * 55) - (59 * 58 * 57 * 56 * 55 * 54)

~Simon

Simon Horwith
Macromedia Certified Instructor
Certified Advanced ColdFusion 5 Developer
Fig Leaf Software
1400 16th St NW, # 500
Washington DC 20036
202.797.6570 (direct line)
www.figleaf.com



-----Original Message-----
From: Michael Corrigan [mailto:[EMAIL PROTECTED]]
Sent: Friday, February 15, 2002 11:28 AM
To: CF-Community
Subject: Re: Anyone good with math?


I thought I covered that in the second example by throwing the ball back 
into the mix after it was chosen which means that the number of combos 
is 60*60*60*60*60*60.  I wrote it as 60^6 because that's how I had to 
notate it in the old piece off shit computers that the university I went 
to used for graphing these functions.  I want to check out that book 
though.  I was terrible at math when I was young, but I always enjoyed 
doing it. It wasn't until I was in my junior-senior year in high school 
that things started to click.  Then I did much better at it in college.  
I help my nephews with their math homework and I think that I give them 
a good perspective because I know what they're going through. 

BTW, he's in seventh grade and is doing algebra.  Not basic algebra 
either.  I was helping him last night figure out how to understand 
direct and inverse variations.  I had to even look at the examples to 
remember how to do it.  But it was fun though.  Now if I can only get 
them to play chess!!

Michael Corrigan
Programmer
Endora Digital Solutions
1900 S. Highland Avenue, Suite 200
Lombard, IL 60148
630-627-5055 x-136
630/627-5255 Fax
  ----- Original Message ----- 
  From: Simon Horwith 
  To: CF-Community 
  Sent: Friday, February 15, 2002 10:23 AM
  Subject: RE: Anyone good with math?


  of course, this changes when you have duplicate values in any of the 
groups,
  and duplicates are not allowed in your result set.  Not too tough to 
figure
  out, but it makes things more interesting, for sure.  By the way, for 
those
  of you interested in learning more about these typres of equations
  (probability and chance)... check out "Innumeracy: Mathematical 
Illiteracy
  and Its Consequences" (by John Allen Paulos).  It's a very good book, 
and is
  a surprisingly easy read.

  ~Simon

  Simon Horwith
  Macromedia Certified Instructor
  Certified Advanced ColdFusion 5 Developer
  Fig Leaf Software
  1400 16th St NW, # 500
  Washington DC 20036
  202.797.6570 (direct line)
  www.figleaf.com



  -----Original Message-----
  From: Michael Corrigan [mailto:[EMAIL PROTECTED]]
  Sent: Friday, February 15, 2002 10:43 AM
  To: CF-Community
  Subject: Re: Anyone good with math?


  Multiply the number allowed in each group by the number allowed in the 

  other groups.  In your case 4*3*5 = 60.  This is actually fun 
because 
  you can figure out combos for everything.  Like the lotto.  If you 
have 
  60 balls in Lotto, and 6 balls are drawn, then the possible combos are 

  60*59*58*57*56*55 = 36,045,979,200.  Therefore your odd are 1 in 
  36,045,979,200 in winning.  Now if you could throw the ball back into 
  the mix each time, then the odds skyrocket because then your possible 
  combos are 60^6 which is 1 in 46,656,000,000.  Sorry. I used to really 

  suck at math but enjoyed doing it. 

  Michael Corrigan
  Programmer
  Endora Digital Solutions
  1900 S. Highland Avenue, Suite 200
  Lombard, IL 60148
  630-627-5055 x-136
  630/627-5255 Fax
    ----- Original Message ----- 
    From: Phillip Broussard 
    To: CF-Community 
    Sent: Friday, February 15, 2002 9:29 AM
    Subject: Anyone good with math?


    I have a math problem and have no idea how to get the answer. Let's 
  say
    that I have 3 groups. The first one has 4 objects, the second has 3
    objects and the third has 5 objects. How would I figure out the 
total
    possible combinations I could have of the three groups if you could 
  only
    have one from each group using coldfusion? 

    Phillip Broussard
    Tracker Marine Group
    417-873-5957


    

  

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