\b([\d]{1,10})(\.\d0)\b
\b = word boundary
([\d]{1,10}) = find digits at least 1 char long to 10 chars long
(\.\d0) = find a decimal point followed by 1 digit, followed by a zero
\b = boundary again to make sure that 999.901 doesn't pass.
On May 18, 2010, at 11:30 AM, G Money wrote:
>
> On Tue, May 18, 2010 at 10:48 AM, Chris Stoner <[email protected]> wrote:
>
>>
>> Try this: [0-9]{0,10}(\.[0-9][0]){0,1}
>>
>> Haven't tested it throughly, but looks like it works. At the very least
>> will give you a starting point. Im sure there is a more elegant way to do
>> it but this should be ok. Or not.
>>
>
> Hey Chris, this is close, but 9999.99 passes, and it shouldn't....any ideas?
>
>
> --
> The suburbs have no charms to soothe
> The restless dream of youth
>
>
>
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