Okay, so you make it past my name, my sense of humor, and my picture, but a
little bit of trigonometry frightens you? There's something wrong here...
Hmm. Must be mathephobic....
--Ben Doom
Programmer & General Lackey
Moonbow Software
: -----Original Message-----
: From: Candace Cottrell [mailto:[EMAIL PROTECTED]]
: Sent: Monday, December 30, 2002 4:15 PM
: To: CF-Community
: Subject: RE: Geometry Question
:
:
: You guys are scaring me....
:
:
:
: Candace K. Cottrell, Web Developer
: The Children's Medical Center
: One Children's Plaza
: Dayton, OH 45404
: 937-641-4293
: http://www.childrensdayton.org
:
:
: [EMAIL PROTECTED]
:
: >>> [EMAIL PROTECTED] 12/30/2002 4:00:04 PM >>>
: Whether the calculation comes out in degrees or radians will depend on
: the
: arcsine/arccosine/arctangent functions used. In CF, it's returned in
: radians (as it should be!).
:
: To convert radians to degrees, simply multiply by 180/pi.
:
: So, in your example, the angle A in degrees would be
: 180/pi*arcsin(x/z)
: or
: 180/pi*arccos(y/z)
: or
: 180/pi*arctan(x/y)
: which (should) all come out to be about
: 63.4 degrees.
:
: did that help?
:
:
:
: --Ben Doom
: Programmer & General Lackey
: Moonbow Software
:
: : -----Original Message-----
: : From: Haggerty, Mike [mailto:[EMAIL PROTECTED]]
: : Sent: Monday, December 30, 2002 3:35 PM
: : To: CF-Community
: : Subject: RE: Geometry Question
: :
: :
: : Oh dear, I must be a little worse off than I thought.
: :
: : Taking a look at what you wrote has yielded little to me. I think I
: may be
: : confused over units, and perhaps converting radians to degrees
: improperly.
: :
: : Would you mind stepping me through your formulas?
: :
: : Say if, in triangle ABC, where B is a right angle and z is the
: hypotenuse,
: : when BC is x and AB is y, we have a value of 5 for y and 10 for x.
: :
: : How do I apply these calculations to determine the angle of A in
: degrees?
: :
: : Thanks,
: : M
: :
: : -----Original Message-----
: : From: Lon Lentz [mailto:[EMAIL PROTECTED]]
: : Sent: Monday, December 30, 2002 3:33 PM
: : To: CF-Community
: : Subject: RE: Geometry Question
: :
: :
: : Oscar
: : Has
: : A
: : Hunk
: : Of
: : Apples
: :
: : Sin(theta) = Opposite/Hypotenuse => Sin(A) = x/z
: : Cos(theta) = Adjacent/Hypotenuse => Cos(A) = y/z
: : Tan(theta) = Opposite/Adjacent => Tan(A) = x/y
: :
: : A = Atan(x/y) = Acos(y/z) = Asin(x/z)
: :
: :
: :
:
:
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