Hello Michael,
thanks. Takes me
in the right direction.

I guess this takes THE First record
of a query.
But I would like to get EVERY First.
Is there such a function ?

Uwe

Saturday, March 15, 2003, 11:36:20 PM, you wrote:

MTT> SELECT TOP 1


MTT> ----- Original Message -----
MTT> From: <[EMAIL PROTECTED]>
MTT> To: "CF-Talk" <[EMAIL PROTECTED]>
MTT> Sent: Saturday, March 15, 2003 4:02 PM
MTT> Subject: OT: SQL first row of duplicates problem


>> Hi list,
>> I have an SQL-problem
>>
>> 29      [EMAIL PROTECTED]  Mister    Mayer   2
>> 26      [EMAIL PROTECTED]  Mister    Mayer   2
>> 4       [EMAIL PROTECTED]   Misses    Miller  2
>>
>>
>> I want to mark every first (but only the first !) line of the
>> lines where the email adress is equal.
>> e.g. with ID = 29 (see above)
>>
>> How can I do this ?
>>
>> SELECT email FROM user
>> GROUP BY Email
>> HAVING Count(*) > 1
>>
>> Gives me the email-record but
>> I am not sure how to mark the FIRST
>> duplicate row.
>>
>> Ideas ? Thanks !
>>
>> Uwe
>>
>> 
MTT> 
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