See my last posting where I have included both the qencode and the
qdecode function. The qencode may indeed wrap through the ascii code
table but, where I am running the left function the values have already
been decoded (de-shifted). All I am trying to do is to get rid of the
random number on the end.
The values I am inputting is:
Input Encoded Output
TID=1 WLG%286G45 TID=1
TID=2 WLG%286G5%3A TID=2
TID=3 WLG%286G63 TID=3
TID=4 WLG%286G73 TID=4
TID=5 WLG%286G84 TID=5
TID=6 WLG%286G93 TID=6
TID=7 WLG%286G%3A6 TID=7
TID=8 WLG%286G%3B9 TID=8
TID=9 WLG%286G%3C3 TID=9
TID=10 WLG%286G437 TID=10
#qencode('TID=1')# should return "WLG%286G45" then
#qdecode('WLG%286G45')# should return the starting value of "TID=1".
Mark W. Breneman
-Cold Fusion Developer
-Network Administrator
Vivid Media
[EMAIL PROTECTED]
www.vividmedia.com
608.270.9770
-----Original Message-----
From: Mark A. Kruger - CFG [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 08, 2003 3:50 PM
To: CF-Talk
Subject: RE: Ok, I give up UDF error
Actually, I tried this function and it works fine for me. What are you
passing into the function? what's the purpose?
Here's a test that passes in cgi.query_string
gives a cryptic strring as a return.
http://dev.mxconsulting.com/sergv2/testSTringUdf.cfm?object=true
Throws an error:
http://dev.mxconsulting.com/sergv2/testSTringUdf.cfm
Throws an error:
http://dev.mxconsulting.com/sergv2/testSTringUdf.cfm?o
If the string is less than 1 character long it throws an error.
I can only assume that something is crazy about the value being passed
IN to the function.
This function appears to take items and shift the ascii character code
value 3 to the left. I'm guessing that the ascii
character code in some cases is less than 3 causing some sort of end
marker to be placed and thus befuddling your
"len( )".
I would do something like:
if(tempStr LT 4)
tempStr = tempStr + 254;
Then your values would "wrap" through the ascii code table.
-Mark
-----Original Message-----
From: Calvin Ward [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 08, 2003 3:16 PM
To: CF-Talk
Subject: Re: Ok, I give up UDF error
What does this do for you?
<cfscript>
function qdecode(urlvars){
var tempurlvars = URLDecode(urlvars);
var strlen = len(tempurlvars);
var tempstr = "";
var i = 1;
var newstr = "";
for(i=1;i lte strlen;i=i+1) {
tempstr = Asc(Mid(tempurlvars, i, 1));
newstr = newstr & Chr(tempstr - 3);
}
strReturn = 'Too Short:' & newstr & ':end';
if (len(newstr)+1)
strReturn = left(newstr,len(newstr)-1);
}
</cfscript>
- Calvin
----- Original Message -----
From: Mark W. Breneman
To: CF-Talk
Sent: Wednesday, October 08, 2003 3:52 PM
Subject: RE: Ok, I give up UDF error
Good question, but no, I have ran the output several times and
checked
all values none are blank.
Mark W. Breneman
-Cold Fusion Developer
-Network Administrator
Vivid Media
[EMAIL PROTECTED]
www.vividmedia.com
608.270.9770
-----Original Message-----
From: Matthew Walker [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 08, 2003 2:44 PM
To: CF-Talk
Subject: Re: Ok, I give up UDF error
Is your input string empty?
----- Original Message -----
From: Mark W. Breneman
To: CF-Talk
Sent: Thursday, October 09, 2003 8:37 AM
Subject: Ok, I give up UDF error
This seems so simple. All I want to do is to trim the last char
from
the
return string. I keep getting this error "Parameter 2 of function
Left
which is now -1 must be a positive integer"
If I hard code a value in the UDF works with out a problem. But
when
I
put in the len(newstr)-1 into the "left" function it seems to
evaluate
to 0.
Can anyone help me out?
<cfscript>
function qdecode(urlvars){
var tempurlvars = URLDecode(urlvars);
var strlen = len(tempurlvars);
var tempstr = "";
var i = 1;
var newstr = "";
for(i=1;i lte strlen;i=i+1) {
tempstr = Asc(Mid(tempurlvars, i, 1));
newstr = newstr & Chr(tempstr - 3);
}
return left(newstr,len(newstr)-1);
}
</cfscript>
Mark W. Breneman
-Cold Fusion Developer
-Network Administrator
Vivid Media
[EMAIL PROTECTED]
www.vividmedia.com
608.270.9770
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