there a way to make it do it recursively until it finds all instances of
\par without a space?
-Deanna
----- Original Message -----
From: "Pascal Peters" <[EMAIL PROTECTED]>
To: "CF-Talk" <[EMAIL PROTECTED]>
Sent: Thursday, December 11, 2003 8:41 AM
Subject: RE: regex help
> due to Outlook, this doesn't look right. It should be :
> "(\\par)([^[:space:]])"
> -----Original Message-----
> From: Pascal Peters
> Sent: donderdag 11 december 2003 15:31
> To: CF-Talk
> Subject: RE: regex help
>
>
> rereplace(mystring, "(\ <file://\\par)([^[:space> \par)([^[:space:]])",
> "\1 \2", "all")
>
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