WebStop Internet Services wrote:
> I have a query that I made that will accept a variable to give the results I
> need. The only problem is, I have to specify the CONTAINER_NO and
> COMPANY_NAME each time and I need to do an aggregate function in here
> somewhere that will take the field "OUT" and subtract it from "IN", then
> multiply it by "RATE" and group the results by Company_Name,
> Container_Number.
IN usually is a keyword in databases. Can you still change that name?
> How do I make it so that the output gives distinct records with COMPANY_NAME
> and CONTAINER_NO along with the SUM of IN minus OUT * RATE and list each
> grouped recordset with the product of the IN-OUT*RATE calculation.
That does not make sense. If you specify the container_no and
company_name like you say above then you will obviously not get
distinct records.
> OUTPUT LIKE THIS:
>
> FIELDS>>> COMPANY_NAME CONTAINER_NO TOTAL RATE
> ----------------------------------------------------------------------------
> ------
> VALUES>>> Joe's Company FWDE44563798764 $200.00
> VALUES>>> Joe's Company DREE44563798764 $400.00
> VALUES>>> Fred's Company BGFE44563798764 $300.00
> VALUES>>> Jan's Company F555544563798764 $600.00
> VALUES>>> Jan's Company 543DE44563798764 $800.00
> VALUES>>> Bert's Company vfdDE44563798764 $1000.00
I think you want:
SELECT
company_name,
container_no,
SUM(("IN" - out) * rate) AS total_rate
FROM
rate_calc
GROUP BY
company_name,
container_no
If that doesn't work, please include your table schema.
Jochem
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