>What's the most efficient way of determining the parent of any item in the
> list and determining that item1 has no parent
perhaps im missing something here, but:
mylist = "item1,item2,item3,item4";
for(i=1; i lte ListLen(mylist);i=i+1){
WriteOutput("I am: "&ListGetAt(mylist,i));
if(i eq 1){
WriteOutput(" and I am the root");
}else{
WriteOutput(" and my parent is:
"&findparent(mylist,ListGetAt(mylist,i)));
}
WriteOutput("<br>");
}
function findparent(nlist,me){
var myparent = "root";
var myindex = ListFind(nlist,me);
if(myindex gt 1){
myparent = ListGetAt(nlist,myindex-1);
}
return myparent;
}
-----Original Message-----
From: Jerry Barnes [mailto:[EMAIL PROTECTED]
Sent: 02 June 2005 15:36
To: CF-Talk
Subject: Re: get parent items from list?
Sounds like an adjaceny list model.
Does the list contain the whole tree or does a list only contain a path from
one node to another while other lists contain other paths?
On 6/2/05, Emmet McGovern <[EMAIL PROTECTED]> wrote:
>
> Brain Meltdown. Maybe someone can help.
>
> I have a list such as (item1,item2,item3,item4,item5). The list can be any
> length. Item1 would be the parent of item2 and item2 would be the parent
> of
> item3 and so on.
>
> What's the most efficient way of determining the parent of any item in the
> list and determining that item1 has no parent?
>
> Thanks,
> Emmet
>
>
>
>
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