Not tested.
To nearest:
a = (a+5) - ((a+5) mod(10))
To always round up
a = (a+9) - ((a+9) mod(10))
-----Original Message-----
From: J W [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 10:24 AM
To: CF-Talk
Subject: Rounding...
I have a whole number rounding problem that I am not sure how solve most
efficiently.
I'd like to take any number and round to the nearest whole 10.
For example:
31 would equal 40
27 would equal 30
155 would equal 160
Any help would be appreciated...
Thanks!
Jeff
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