The first will always return one row.

I suppose I could go that route

On 12/8/05, Dave Watts <[EMAIL PROTECTED]> wrote:
>
> > this is the meat of the SP
> >
> > @value_needed is the value I need to get. it needs to be
> > a.adviceID from the first select.
> >
> > SELECT
> >     a.userIDFK, a.adviceID,
> >     UD.userPhotoPath AS adviceseekerPhotoPath,
> >     UD.userPhoto AS adviceSeekerPhoto,
> >     UD.userSensitivity AS adviceSeekerSensitivity,
> >     UD.userCareer AS adviceSeekerCareer,
> >     UD.userHumor AS adviceSeekerHumor,
> >     UD.userPersonality AS adviceSeekerPersonality,
> >     UD.userIntelligence AS adviceSeekerIntelligence,
> >     UD.userDescription AS adviceseekerdescription
> > FROM Advice a INNER JOIN userData UD on A.userIDFK = UD.UserID
> > WHERE a.userIDFK = @Input_userID
> >
> > -- select data on "the other people"
> > SELECT
> >     aa.Advice_aboutID, aa.AdviceIDFK, aa.PhotoDescription,
> > aa.adviceSensitivity, aa.adviceCareer, aa.adviceHumor,
> > aa.advicePersonality,
> >     aa.adviceIntelligence, aa.PhotoPath, aa.Photo
> > FROM Advice_about aa
> > WHERE aa.adviceIDFK = @value_needed
> >
> > -- select existing ratings
> > SELECT
> >     ar.adviceIDFK, ar.ratingUserID, ar.adviceFeedback, ar.rating,
> > UD.userLogin
> > FROM Advice_ratings ar LEFT OUTER JOIN userData UD on
> > ar.ratingUserID =
> > UD.UserID
> > WHERE ar.adviceIDFK = @value_needed
> > GROUP BY ar.ratingUserID, UD.userLogin, ar.adviceIDFK,
> > ar.adviceFeedback, ar.rating
>
> Will the first query return a single value in all cases? If not, the whole
> thing doesn't make much sense. In any case, why not write the thing as one
> big SELECT statement?
>
> Dave Watts, CTO, Fig Leaf Software
> http://www.figleaf.com/
>
> Fig Leaf Software provides the highest caliber vendor-authorized
> instruction at our training centers in Washington DC, Atlanta,
> Chicago, Baltimore, Northern Virginia, or on-site at your location.
> Visit http://training.figleaf.com/ for more information!
>
>
> 

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