Gavin, this is what I got, not sure if it is correct, but... here's the
logic.
If you got 0.000385 people per 1 millisecond, that is the equivalent of 1
person per 2597.40265 milliseconds (divide both by 0.000385). That means
that 2 people in 2*2597.40265 = 5194.8052 milliseconds. So, that's more a
fact than a % chance of something happening.
So 2 people per 5194.8052 milliseconds. That means that the chance of 2
people hitting the site in the same millisecond is 1/5194.8052 which is
0.0001925 (which essentially means 0.019%). Without getting into
statistical details about 0.025 alphas and bell curves... I would say it is
pretty much impossible that 2 people will hit the same site at the exact
same time (millisecond), let alone the same page.
disclaimer: I am not a stats person (took a few courses but no more)... but
I thought it would be fun to give it a shot.
Good luck
Nadir
-----Original Message-----
From: Gavin Myers [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, October 11, 2000 1:02 PM
To: CF-Talk
Subject: slightly ot: math question, needed for cold fusion programming
Lets say you have 1 page that scores 1,000,000 unique visitors a month
here's what I came up with:
1,000,000/30/24/60/60/1000 = 0.000385
So that means that 0.0003 people a milisecond hit the sight, correct?
what is the % chance of 2 people hitting on the same milisecond (and math
equation for that?)
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