Then I missed that condition.

If the premise is the absence of triple multiplicities, then you will hav
items^slots - itemslots, thus 3^3 - the permutations were one item has all
three items slots sets.  3^3 - 3 and thus 24.  This changes quickly if you
have more items than slots and have to determine which multiplicities you
want to exclude.

Teddy


On 11/29/06, Ian Skinner <[EMAIL PROTECTED]> wrote:
>
> It is just a permutation set of all possible combinations of three items
> that allow repeats.
>
> But it was NOT a set of all possible combinations.  For example 000, 888
> and FFF were not desired results for my problem.
>
>
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