A slightly different method (simply because I felt like it).
<cfscript>
for (i=1; i LTE 100; i=i+1)
{
if (i\3 EQ i/3) WriteOutput('fizz');
if (i\5 EQ i/5) WriteOutput('buzz');
if (i\5 NEQ i/5 AND i\3 NEQ i/3) WriteOutput(i);
WriteOutput('<br/>');
}
</cfscript>
> I was reading an article titled (http://www.codinghorror.
> com/blog/archives/000781.html). The article talked about programmers
> applying for positions and not being able to write code FOR the
> position for which they're applying. Anyway, the author came up with a
> series of small coding challenges meant to prove that the applicant
> could in fact write code.
>
> Here's the specific one he mentioned:
> Write a program that prints the numbers from 1 to 100.
> But for multiples of three print "Fizz" instead of the number.
> For the multiples of five print "Buzz".
> For numbers which are multiples of both three and five print
> "FizzBuzz".
>
> Here's what I came up with, I'd be interested in seeing what you guys
> might come up with. It took me about 4 or 5 minutes.
>
> <cfoutput>
> <cfloop index="i" from="1" to="100">
> <cfif NOT i MOD (3*5)>
> fizzbuzz
> <cfelseif NOT i MOD 5>
> buzz
> <cfelseif NOT i MOD 3>
> fizz
> <cfelse>
> #i#
> </cfif>
> <br>
> </cfloop>
</cfoutput>
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