Richard,
A simple way to do this is to use a "Tally" table. A "Tally" table
contains one column, ID, that contains numbers from 1 to [x]. You can
then do joins against this table to do what you are looking for. Here's
an example:
SELECT t.ID,
a.Taken,
a.assessment_ID
FROM Tally as t
LEFT OUTER JOIN assessment a on
YEAR(a.Taken) = YEAR(DATEADD(YEAR,-(t.ID -
1),now()))
WHERE t.ID <= 3
AND youth_id = 'X'
That will output NULLs for years that don't exist. Let me know if you
have any questions.
Regards,
Chris
-----Original Message-----
From: Richard Dillman [mailto:[EMAIL PROTECTED]
Sent: Monday, September 17, 2007 8:13 PM
To: CF-Talk
Subject: Re: Pivot table confusion
OK maybe I need to take a step back and give you some more detail.
Or maybe I'm just not going to comprehend what you guys are telling me.
I have a single table called assessment with these fields.
[assessment_id] [int] IDENTITY(1,1) NOT NULL
[youth_id] [varchar](26) NOT NULL
[org_id] [varchar](26) NOT NULL
[Taken] [datetime] NOT NULL
[assessment_type] [int] NOT NULL
Ive tried any number of answers from googling, and Ive been on this all
day
and I simply don't follow what your doing. But this is what I'm after.
I'm only going to display 3 years so
#Year(dateadd("yyyy",-2,now()))# Through #year(now())#
but the part i get lost at is creating the empty cells for the values
that
Don't exist.
-------------------2005--2006--2007--Total
------------------------------------------
assessment_type 1-----0-----5----10-----15
assessment_type 2-----3-----0----11-----14
assessment_type 3-----5-----5-----9-----19
------------------------------------------
Grand Totals----------8----10----30-----48
I really appreciate all the help but you would think their was an easy
way
to do this with SQL. Seems it would be something you would need rather
often. What I keep coming up with is the following table with the type
repeated if theirs more than one year.
-------------------2005--2006--2007--Total
------------------------------------------
assessment_type 1-----------5----10-----15
assessment_type 2-----3----------11-----14
assessment_type 3-----5------------------5
assessment_type 3-----------5------------5
assessment_type 3-----------------9------9
------------------------------------------
Grand Totals----------8----10----30-----48
----Totally Confused----
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