I ended up trying this

#replace(noBreak(txt), "#Chr(13)#", "<br />", "All")#

and it works fine... is that what you
were getting at below?  I didn't quite understand the "before and after"
aspect.

Rick

> -----Original Message-----
> From: Bobby Hartsfield [mailto:[EMAIL PROTECTED]
> Sent: Friday, October 12, 2007 11:19 PM
> To: CF-Talk
> Subject: RE: How to write this regex?
> 
> Well for display, you would have to use a BR for a line break anyway...
> unless its wrapped in pre tags...
> If you still need to... you could just replace #chr(13)##chr(10)# with
> <br
> /> beforehand then put them back afterwards.
> 
> Before.... replace(str, "#chr(13)##chr(10)#", "<br />", "all")
> After.... replace(str, "<br />", "#chr(13)##chr(10)#", "all")
> 
> ..:.:.:.:.:.:.:.:.:.:.:.:.:.:.:.:.:.
> Bobby Hartsfield
> http://acoderslife.com
> 
> -----Original Message-----
> From: Rick Faircloth [mailto:[EMAIL PROTECTED]
> Sent: Friday, October 12, 2007 7:17 PM
> To: CF-Talk
> Subject: RE: How to write this regex?
> 
> Ok, Bobby... that works, thanks!
> 
> However, now I have to use <br> whenever I want a carriage return.
> What about having it ignore the Chr(13) ?
> 
> Rick
> 
> > -----Original Message-----
> > From: Bobby Hartsfield [mailto:[EMAIL PROTECTED]
> > Sent: Friday, October 12, 2007 4:16 PM
> > To: CF-Talk
> > Subject: RE: How to write this regex?
> >
> > Not the end result.. the end result is just...
> >
> > #noBreak(str)#
> >
> > :-)
> >
> > ..:.:.:.:.:.:.:.:.:.:.:.:.:.:.:.:.:.
> > Bobby Hartsfield
> > http://acoderslife.com
> >
> >
> >
> >
> >
> 
> 
> 
> 

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