ok.
thanks guys
i will look at it once my eyes relax a bit.
so should i first
var aSortTables = $("table.tablesorterLQ");
for ( var i = 1; i < aSortTables.length; i++ )
to creat the +1 count?
or is this not needed.
i am not familar with the short cut you mentioned.
i dont see in Matts test where the i is invoked in the top part of the js?
sorry if i dont make any sense.
On Jan 11, 2008 4:34 PM, Matt Williams <[EMAIL PROTECTED]> wrote:
> On Jan 11, 2008 2:43 PM, Sonny Savage <[EMAIL PROTECTED]> wrote:
> > jQuery might even have a shortcut that assigns all the elements of the
> array
> > at once:
> > $("table.tablesorterLQ").tablesorter({sortList:[[0,0],[0,1]], widgets:
> > ['zebra']});
>
> Sonny is right. What he has should work. Here is some code I have that
> makes the 2 tables sortable.
>
> <link rel="stylesheet" type="text/css" media="screen" href="style.css"
> charset="utf-8" />
> <script src="jquery.js" type="text/javascript"></script>
> <script type="text/javascript" src="jquery.tablesorter.min.js"></script>
> <script type="text/javascript">
> $(document).ready(function(){
> $('.tablesorter').tablesorter({
> sortList: [[0,0],[0,1]],
> widgets: ['zebra']
> });
> });
> </script>
>
> <cfoutput>
> <cfloop from="1" to="2" index="i">
> <table class="tablesorter" id="tblRep#i#">
> <thead>
> <tr>
> <th>name</th>
> <th>number</th>
> </tr>
> </thead>
> <tbody>
> <tr>
> <td>Aaron #i#</td>
> <td>20</td>
> </tr>
> <tr>
> <td>Bill #i#</td>
> <td>10</td>
> </tr>
> </tbody>
> </table>
> </cfloop>
> </cfoutput>
>
> --
> Matt Williams
> "It's the question that drives us."
>
>
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