The COUNT( ) function will never return NULL.  So "isNull(count(*))" will
never trigger.  Count(*) will always return an int - so using isNULL and
"count" together is not possible - plus you are mixing data types if you are
trying to return a 0.00001 to a function call designed to return an int.


-----Original Message-----
From: morchella [mailto:[EMAIL PROTECTED] 
Sent: Thursday, January 17, 2008 9:03 AM
To: CF-Talk
Subject: SQL: ISNULL, NULLIF problem

i have been trying to figure out how to check for null like whats done in
this url:
http://www.bennadel.com/blog/984-Using-NULLIF-To-Prevent-Divide-By-Zero-Erro
rs-In-SQL.htm


SELECT
(
ISNULL(
(45 / NULLIF( 0, 0 )),
0
)
) AS value

how would i re write the code below to check for null i can then get rid of
the + 0.00000001

(SELECT COUNT(*)
FROM Emp
WHERE emp_assID = rEmp.empID AND addSale = 1) * 100 / (SELECT COUNT(*) +
0.00000001 FROM Emp WHERE emp_assID = rEmp.empID AND ((Emp.Qal = 4) OR
(Emp.addSale = 1))) AS perEmp


i tried:
(SELECT ISNULL( COUNT(*)
FROM Emp
WHERE emp_assID = rEmp.empID AND addSale = 1) / NULLIF( (SELECT COUNT(*)
FROM Emp WHERE emp_assID = rEmp.empID AND ((Emp.Qal = 4) OR (Emp.addSale =
1))), 0 )), 0
)
) AS perEmp

but i get Incorrect syntax near the keyword 'FROM'.
any help would be great...
thanks



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