Theres 2 methods for doing it.
<!--- Method #1 --->
<cfloop index="count" from="1" to="6" step="1">
#count#
</cfloop>
<!--- Method #2 --->
<cfset x="1">
<cfloop index="count" from="1" to="6" step="1">
#x#
<cfset x=x+1>
</cfloop>
Now just add a condition in there. It makes it easy since you know that you
only want 6 numbers. You can set up the if/else anyway you like. take a look
below.
<cfif #count# IS "1">
<cfelseif #count# IS "3">
<cfelseif #count# IS "5">
</cfif>
Sincerely,
Mike
>From: "Jason Larson" <[EMAIL PROTECTED]>
>Reply-To: [EMAIL PROTECTED]
>To: CF-Talk <[EMAIL PROTECTED]>
>Subject: Finding an Odd Number
>Date: Mon, 20 Nov 2000 08:57:34 -0700
>
>
>Can someone help me out?
>
>I have a cfloop that loops 6 times, I want to be able to be able to output
>what loop number the current loop is on, and tell if the number is even or
>odd.
>
>Any help would be greatly appreciated
>
>Thanks
>Jason Larson
>[EMAIL PROTECTED]
>
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