> If i have a list like:
>
> 2,10,3,1,2,9,9,2
>
> what is the easiest way to parse out the dupes to make the list:
> 2,10,3,1,9
>
May not be the easiest, but ...
<cfset originalList="2,10,3,1,2,9,9,2">
<cfset tmpList="">
<cfloop index="item" list=originalList>
<cfif(NOT ListFindNocase(tmpList,item)>
<cfset tmp=ListAppend(tmpList,item)>
</cfif>
</cfloop>
OR,
You could use ListValueCountNoCase(), but you'll
end up spending more processing time as you'll have
to reloop every time you find a return > 1 and do a
ListDeleteAt() for the 2nd+ occurrences.
Or,
You could build a structure and use StructKeyExists(),
..... etc.
In short there area lot of way to code what you
want to do ... "easiest" is up to you, but the first method
I outlined should be reasonably quick and simple - it does
operate in linear time so there might be a faster method.
Pan
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