So, this problem has been sitting in my kitchen. The math has been
proved and a good solution using database table joins provided, but I
just *knew* this could be solved with looping.
Of course it could be hard coded:
<cfoutput>
<cfloop from="0" to="1" index="a1">
<cfloop from="0" to="1" index="a2">
<!--- loops for a3 to a21 --->
<cfloop from="0" to="1" index="a22">
#yesNoFormat(a1)# #yesNoFormat(a2)# <!--- output for a3 to
a21 ---> #yesNoFormat(a22)#<br>
</cfloop>
</cfloop>
<!--- loop closes for a3 to a21 --->
</cfloop>
</cfoutput>
But that was too much work and this should have been solvable with
iteration. It took me a couple of days to scrape together a few free
minutes to come up with this:
<cffunction name="it" output="yes">
<cfargument name="depth" type="numeric" required="yes">
<cfargument name="answerKey" type="string" required="no" default="">
<cfset var i = 0>
<cfif depth-- GT 0>
<cfloop from="0" to="1" index="i">
#it(depth,answerKey & ' ' & yesNoFormat(i))#
</cfloop>
<cfelse>
#answerKey#<br/>
</cfif>
</cffunction>
<cfoutput>#it(22)#</cfoutput>
I leave it to somebody else to run the code to generate the 4,194,304
combinations, but it works well up to 10 'questions'.
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