Sweet! Many years ago, in high school Algebra class, I would have been able
to figure that out. It's amazing what we forget.

-----Original Message-----
From: Barney Boisvert [mailto:bboisv...@gmail.com] 
Sent: Wednesday, November 25, 2009 2:23 PM
To: cf-talk
Subject: Re: Round to the nearest .5 value


Assuming 'n' is your number, use #round(n * 2) / 2#

For example:

3.21 * 2 == 6.42
round(6.42) == 6
6 / 2 == 3

3.31 * 2 = 6.62
round(6.62) == 7
7 / 2 == 3.35

cheers,
barneyb



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