This isn't the point though. He wants to convert a string to an array of letters. =) The output is just an example.
Rick On Thu, Sep 23, 2010 at 9:33 PM, Michael Grant <[email protected]> wrote: > > The following is less code but would it execute slower because of the mid? > I can't test right now. > > <cfset myString = "This is funner" /> > <cfloop from="1" to="#len(myString)# index="x"> > <cfoutput>Position #x# = #mid(myString,x,1)#<br/></cfoutput> > </cfloop> > > On Thu, Sep 23, 2010 at 9:28 PM, Rick Root <[email protected]> wrote: > >> >> <Cfset mySTring = "This is fun"> >> <cfset myArray = mySTring.split('')> >> <cfloop from="1" to="#ArrayLen(myArray)#" step="1" index="x"> >> <cfoutput>Position #x# = #myArray[x]#<br/></cfoutput> >> </cfloop> >> >> Yes, it's THAT easy. If you run the code above you'll see this: >> >> Position 1 = >> Position 2 = T >> Position 3 = h >> Position 4 = i >> Position 5 = s >> Position 6 = >> Position 7 = i >> Position 8 = s >> Position 9 = >> Position 10 = f >> Position 11 = u >> Position 12 = n >> >> Note that the first element is an empty string. >> >> Rick >> >> > > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~| Order the Adobe Coldfusion Anthology now! http://www.amazon.com/Adobe-Coldfusion-Anthology-Michael-Dinowitz/dp/1430272155/?tag=houseoffusion Archive: http://www.houseoffusion.com/groups/cf-talk/message.cfm/messageid:337443 Subscription: http://www.houseoffusion.com/groups/cf-talk/subscribe.cfm Unsubscribe: http://www.houseoffusion.com/groups/cf-talk/unsubscribe.cfm
