If I do this it snaps into place also. No fade in.
function swapImages(imageName) {
$("#beautyImage").html('<img src="/output/9305B06559F4D04C37ED27103EBFB959.jpg"
style="margin-left:5px;">').fadeIn('slow');
}
-----Original Message-----
From: Michael Grant [mailto:[email protected]]
Sent: Thursday, October 21, 2010 2:43 PM
To: cf-talk
Subject: Re: (ot) jQuery
I don't see why it wouldn't be. Does fadeIn() work if you do it on it's own?
On Thu, Oct 21, 2010 at 2:40 PM, Chad Gray <[email protected]> wrote:
>
> Thanks for the suggestions, but still now luck. Maybe the get() is not
> compatible with fadeIn()?
>
>
>
> -----Original Message-----
> From: Tony Bentley [mailto:[email protected]]
> Sent: Thursday, October 21, 2010 2:39 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> function swapImages(imageName) {
> $.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
> '&width=372&height=465',{},function(data) {
> $("#beautyImage").html(data).fadeIn('slow');
> });
> }
>
>
>
>
>
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