Did you try

numberFormat(myNum, ",9.9")

?


On 6/27/2012 1:34 PM, Richard White wrote:
> I think i may need to be clearer on what i am trying to achieve:
>
> I have any form of number, they could be integer or floats and with varying 
> decimal places such as:
>
> 11
> 11111.111111111
> 11.11
> 1.1
> 111111111111111111111.11111111111111111111
>
> etc....
>
> I need to have a function that simply adds the thousand separators and 
> returns exactly how they were, such as:
>
> 11
> 11,111.111111111
> 11.11
> 1.1
> 111,111,111,111,111,111,111.11111111111111111111
>
> i was hoping there was an existing function that would handle this but its 
> looking like i am going to have to develop a custom function that handles 
> this as the number either handles integers OR floats but not both?
>
> thanks
>
>
>
>
>
>> Then try
>>
>> numberFormat(myNum, ",9.9")
>>
>> thanks Jason, although this strips off all the decimals
>>
>>> numberFormat(myNum, ",9")
>>>
>>> thanks for your help Robert although that didnt work as it returns lots of
>>> zeros after the decimal place.
>>>
>>> for example: 112221.111 got changed to 112,221.11100000000000
>>>
>>> thanks
>>>
>>> com/austin_
>
> 

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