By using the mod function on queryname.CurrentRow.
Create this struct to hold your two color values.
<CFSCRIPT>
stColor = STRUCTNEW();
stColor[0] = '##FFFFFF';
stColor[1] = '##CCCCCC';
</CFSCRIPT>
Then place this code inside of each td:
BGCOLOR="#EVALUATE("stColor[QueryName.CurrentRow MOD 2]")#"
-
Nate Smith,
Lead Developer
Macromedia Coldfusion 5 Certified Professional
Macromedia Certified Web Site Developer
[EMAIL PROTECTED]
www.doceus.com
-----Original Message-----
From: Chad Gray [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, August 21, 2001 2:39 PM
To: CF-Talk
Subject: Alternating BG colors on a <TD>
I have done this in the past, but cant remember how i did it.
When using a <CFOUTPUT QUERY=""> tag on a table how do i get every other
<TD> to have a background color?
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RE: Alternating BG colors on a
Nate Smith
Tue, 21 Aug 2001 12:12:06 -0700
- Re: Alternating BG colors on a <TD> Clint Tredway
- Re: Alternating BG colors on a <TD> Don Vawter
- RE: Alternating BG colors on a <TD> Carlisle, Eric
- RE: Alternating BG colors on a <TD> Nate Smith
- RE: Alternating BG colors on a <TD> Dan G. Switzer, II
- RE: Alternating BG colors on a <TD> Kevin Mansel
- RE: Alternating BG colors on a <TD> Sicular, Alexander
- RE: Alternating BG colors on a <TD> Carlisle, Eric
- RE: Alternating BG colors on a <TD> Raymond Camden
- RE: Alternating BG colors on a <TD> Nate Smith
- RE: Alternating BG colors on a <TD> Jann VanOver
Reply via email to
Nate Smith Tue, 21 Aug 2001 12:12:06 -0700
- Re: Alternating BG colors on a <TD> Clint Tredway
- Re: Alternating BG colors on a <TD> Don Vawter
- RE: Alternating BG colors on a <TD> Carlisle, Eric
- RE: Alternating BG colors on a <TD> Nate Smith
- RE: Alternating BG colors on a <TD> Dan G. Switzer, II
- RE: Alternating BG colors on a <TD> Kevin Mansel
- RE: Alternating BG colors on a <TD> Sicular, Alexander
- RE: Alternating BG colors on a <TD> Carlisle, Eric
- RE: Alternating BG colors on a <TD> Raymond Camden
- RE: Alternating BG colors on a <TD> Nate Smith
- RE: Alternating BG colors on a <TD> Jann VanOver

