Okies, well the code I sent will do the date but (from your example) will give this 
result:

21/2/2003
20/2/2003

rather than:

21/02/2003
20/02/2003

if that's important then I'm not sure how to force sql server to give you the extra 0's

- James

-----Original Message-----
From: Balaji [mailto:[EMAIL PROTECTED]]
Sent: Friday, 21 February 2003 15:48
To: CFAussie Mailing List
Subject: [cfaussie] RE: pick record with same date irnoring time



Hi James,

I want to pick all distinct dates ignoring time..

there could be something like this.

21/02/2003 10:00:03
21/02/2003 12:06:04
20/02/2003  01:51:22
20/02/2003  01:57:22

I want this result.

21/02/2003
20/02/2003

--Bal


-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]On Behalf Of James
MacPherson
Sent: Friday, February 21, 2003 3:52 PM
To: CFAussie Mailing List
Subject: [cfaussie] RE: pick record with same date irnoring time


try something like:

SELECT *
FROM tablename
WHERE CONVERT(nvarchar(2), DAY(tablename.column)) + '/' +
CONVERT(nvarchar(2), MONTH(tablename.column)) + '/' + CONVERT(nvarchar(4),
YEAR tablename.column)) = 'date goes here'



-----Original Message-----
From: Balaji [mailto:[EMAIL PROTECTED]]
Sent: Friday, 21 February 2003 15:38
To: CFAussie Mailing List
Subject: [cfaussie] pick record with same date irnoring time


Hi,

I want to pick records from a table with distinct dates ignoring time.

suggestions pls..

--Bal

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