whatever, just close this discussion, its getting nowhere..
Whether that is because I am not explaining myself well enough, or whether the 
discussion is not followed from the first email I do not know.
I am giving up on this one.
Thanks all..

-----Original Message-----
From: Matthew Walker [mailto:[EMAIL PROTECTED]
Sent: Monday, 1 December 2003 8:44 AM
To: CFAussie Mailing List
Subject: [cfaussie] Re: [OT] JS RegEx


[^a-z\.,] is not a string of characters. It's a class, which will match
exactly one character in that class. 

[^a-z\.,]+ is a string of characters.

> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:bounce-cfaussie-
> [EMAIL PROTECTED] On Behalf Of Taco Fleur
> Sent: Monday, 1 December 2003 10:39 a.m.
> To: CFAussie Mailing List
> Subject: [cfaussie] Re: [OT] JS RegEx
> 
> Hi Graham,
> 
> not sure if your regex would work, but I do know it would not work for me,
> as the regex string is not just one character but a long string of
> characters like [^a-z\.,] etc. so I would not be able to specify the
> backreference.
> example
> 
> obj.value = obj.value.replace("[^a-z\.,'\-\s]", "");
> 
> 
> 
> -----Original Message-----
> From: Graham Cook [mailto:[EMAIL PROTECTED]
> Sent: Friday, 28 November 2003 11:42 PM
> To: CFAussie Mailing List
> Subject: [cfaussie] Re: [OT] JS RegEx
> 
> 
> Hi Taco, I'm a newbie at regular expressions, but looking at my O'Reilly
> book they give the example to remove any doubled words:
> <cfset NoDupes = ReReplaceNoCase("I would like to go to to the park","([A-
> Z]+)[ ]+\1","\1","\1","ALL">
> 
> >From that could the extrapolation for your situation be along the lines:
> "([']+)[]+\1","\1","\1","ALL"
> 
> Regards
> Graham Cook
> 
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