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Il 04/09/2014 15:13, Abramo Bagnara ha scritto:
>
> For the following source
>
> void f() {
> char *p;
> const char *cp;
> p == cp;
> p != cp;
> p < cp;
> p <= cp;
> p > cp;
> p >= cp;
> p - cp;
> }
>
> clang (unexpectedly for me) emits an implicit cast from const char * to
> char * (i.e. it remove a qualifier) for all the relational and equality
> operator, but it (expectedly) does not emit one for the subtraction.
>
> AFAIK the C standard does not require any conversion for relational and
> equality operator (just like for subtraction).
>
> Do we have a reason to add the implicit casts or it is a bug?
>
--
Abramo Bagnara
BUGSENG srl - http://bugseng.com
mailto:[email protected]
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