On Jan 24, 2013, at 5:35 PM, Richard Smith <[email protected]> wrote:
>> >> So, I need to mention that it is a constant expression. >> Currently it says. overflow of constant expression results in value %0 of >> type %1 >> I think your suggesting would be something like: >> >> "overflow of constant expression; resulting value is %0 of type %1" > > The warning also catches cases which are not constant expressions, such as... > > int a; > int b = (a, 65537) * 65537; Good observation. In r r173461. - Fariborz _______________________________________________ cfe-commits mailing list [email protected] http://lists.cs.uiuc.edu/mailman/listinfo/cfe-commits
