efriedma added a comment. I don't think that was the approach @rsmith was suggesting; you don't need to wrap every possible kind of expression. Rather, at the point where the expression is required to be constant, add a single expression which wraps the entire expression tree to indicate that. So for "constexpr int c = 10+2;", the expression tree for the initializer is something like ConstExpr(BinaryOperator(IntegerLiteral, IntegerLiteral)).
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