alexey.lapshin marked 2 inline comments as done. alexey.lapshin added a comment.
will correct all mistakes. please check explanations for the questions. ================ Comment at: include/clang/Basic/AttrDocs.td:2655 + dependence violated. This constant interval(in cycles) between the start + of iterations called initiation interval. Cycles number of one iteration + of newly generated loop matches with Initiation Interval. For further ---------------- aaron.ballman wrote: > is called the initiation interval. > > I can't quite parse the second sentence, though. Is it trying to say that the > initiation interval is the number of cycles for a single iteration of the > optimized loop? Not quite right : initiation interval is not a number of cycles for a single iteration of the optimized loop. But initiation interval matches with number of cycles for a single iteration of the optimized loop. Initiation interval is the number of cycles between next and previous iteration of original loop. New loop created so that single iteration of the optimized loop has the same number cycles as initiation interval( thus every new iteration of original loop started each time when new iteration of optimized loop started - difference between iterations is initiation interval). trying to rephrase : number of cycles for a single iteration of the optimized loop matches with number of cycles of initiation interval. ================ Comment at: include/clang/Basic/AttrDocs.td:2676 + the software pipeliner to try the specified initiation interval. + If schedule found the resulting loop iteration would have specified + cycle count. The positive number greater than zero can be specified: ---------------- aaron.ballman wrote: > I'm can't quite parse this sentence either. Is it trying to say that the > scheduler will try to find a loop iteration cycle count that most-closely > matches the specified initiation interval? I wanted to say that pipeliner will try to find a schedule that exactly matches the specified initiation interval. And if schedule would be found then single iteration of the optimized loop would have exactly the same amount of cycles as initiation interval. trying to rephrase : If schedule would be found then single iteration of the optimized loop would have exactly the same amount of cycles as initiation interval has. CHANGES SINCE LAST ACTION https://reviews.llvm.org/D55710/new/ https://reviews.llvm.org/D55710 _______________________________________________ cfe-commits mailing list cfe-commits@lists.llvm.org http://lists.llvm.org/cgi-bin/mailman/listinfo/cfe-commits
