aabbaabb added a comment.

In D101139#2718057 <https://reviews.llvm.org/D101139#2718057>, @phosek wrote:

> In D101139#2713530 <https://reviews.llvm.org/D101139#2713530>, @aabbaabb 
> wrote:
>
>> The python script assumes relative directory while finding things. For 
>> example, for resources folder, it uses os.path.join(this_dir, 'resources') 
>> in report.py, which means resource need to be in the same dir as report.py. 
>> Similarly for the libscanbuild. it assumes the library is always at one 
>> level up from bin folder. Installing them to different directories would 
>> break the script.
>
> We could reorganize things to match the final layout, that's the strategy 
> that https://github.com/llvm/llvm-project/tree/main/clang/tools/scan-build 
> uses as well.
>
> In D101139#2713551 <https://reviews.llvm.org/D101139#2713551>, @aabbaabb 
> wrote:
>
>> libear is built dynamically at runtime from build_libear function in 
>> libear/__init__.py which would be called by libscanbuild/analyze.py. It is 
>> not built statically.
>
> Could we modify the code to avoid building libear at runtime and instead 
> build it with CMake. Is libear even needed when using compilation database?

If i copy libscanbuild/resources to out/share/, libscanbuild to 
out/libscanbuild, bin/* to bin, then resources would be in a different layout 
than the original src. You mean modifying the original source and move 
libscanbuild/resources out to share/resources and update the code reference?

We are not using libear, we are only using analyze-build not scan-build. For 
our usage, I could define a target that only copies analyze-build, not 
scan-build. However, I am not sure whether this is appropriate. On the other 
hand, building libear statically might require significant change to the code.


Repository:
  rG LLVM Github Monorepo

CHANGES SINCE LAST ACTION
  https://reviews.llvm.org/D101139/new/

https://reviews.llvm.org/D101139

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