shafik added a comment.

Are you sure it is failing on the line you indicated? After looking at the 
code, a little before that line we have:

  Result = APValue(APValue::UninitArray(), NumEltsToInit, NumElts);

which should assure that we have an array at this point. Looking at the result 
of the code prior to this they evaluate the check for `Result.isArray()` and so 
we should be consistent.


CHANGES SINCE LAST ACTION
  https://reviews.llvm.org/D128248/new/

https://reviews.llvm.org/D128248

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