aaron.ballman added inline comments.

================
Comment at: clang-tidy/modernize/RawStringLiteralCheck.cpp:71
+  // supported by specific code pages only.
+  if (Bytes.find_if_not(isASCII) != StringRef::npos)
+    return false;
----------------
zinovy.nis wrote:
> aaron.ballman wrote:
> > zinovy.nis wrote:
> > > aaron.ballman wrote:
> > > > I am starting to think that this functionality should be refactored 
> > > > because the check is now O(N^2) in the worst case because all of the 
> > > > bytes of the string need to be touched twice. It would be nice for 
> > > > performance reasons to combine this so that there's only a single pass 
> > > > over all of the characters.
> > > > 
> > > > What do you think?
> > > Sorry, but why O(N^2)? `isASCII` is O(1), it's just `return C<=127`. 
> > > `find_if_not` is O(N).
> > The `find_if_not()` call you add touches every character in the string to 
> > see if it's ASCII and it all characters are ASCII, then `containsEscape()` 
> > calls `find()` which touches every character again (assuming the searched 
> > character is never encountered).
> > 
> > Looking a bit deeper, `isRawStringLiteral()` also calls `find()`, but it 
> > asserts that the character is found, so not every character is touched in 
> > the string and it should find a the searched character quite quickly.
> OK, I'll see how to combine theses checks into a single one.
> 
> But anyway I see only 2*O(N), not O(N^2) here.
Oh, derp, that's my thinko -- sorry! You are correct, that's 2 * O(N) and not 
O(N^2).


https://reviews.llvm.org/D45932



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