v=:10?.@$20
   v
14 16 8 6 5 8 6 16 16 19
   (~.v) ,. (((~.v) i. v) #/. v)
14 1
16 3
 8 2
 6 2
 5 1
19 1
   (~. ,. (i.~ ~.)~ #/. ])v
14 1
16 3
 8 2
 6 2
 5 1
19 1


R.E. Boss


-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Joe Bogner
Sent: woensdag 28 augustus 2013 14:52
To: [email protected]
Subject: Re: [Jchat] programming without loops

I took Ric's solution and expanded it to better understand the steps
involved. My brain doesn't yet think in terms of @ [:

NumMovies=: 26

NumStudents=: 100

Groups=: NumStudents $ i.3


Votes=: ?. NumStudents$NumMovies


v=: Groups,. Votes


VotesFreqTbl=: (~.v) ,. (((~.v) i. v) #/. v)


VotesFreqTbl=: VotesFreqTbl \: 2{"1 VotesFreqTbl NB. sort by votes across
groups

VotesFreqTbl=: (~: 1{"1 VotesFreqTbl) # VotesFreqTbl NB. deduplicate movie
entries

MovieProgram=: (0{"1 VotesFreqTbl) ((3&{.))/. VotesFreqTbl NB. take top 3
choices for each

MovieProgram


It's more verbose. I found it easier to understand when tying it back to the
vocabulary page examples.

This statement could use some simplification. It was too heavy on
parentheses for my taste -- even though that's how I started building it. I
would take one piece and then compose it with it the next.

VotesFreqTbl=: (~.v) ,. (((~.v) i. v) #/. v)


(nub v) stitch  (((nub v) index v) count per group v)


When I was writing it, I would start with each piece in parens to work out
what it was doing.


It seems like that might be a good application of a cap or a fork. I haven't
gotten to that level of understanding yet.  Could someone please help in the
syntax?


In my mind, it would be like this:


 (~. ] ,. ~.] i. ] #/. ]) v


Or maybe there is a better way.


Thanks for the help



On Wed, Aug 28, 2013 at 12:01 AM, Ric Sherlock <[email protected]> wrote:

> The code below follows Brian's approach but attempts to simplify some 
> of the array manipulation.
>
> NumMovies=: 26
> NumStudents=: 100
> Groups=: NumStudents $ i.3
>
> Votes=: NumStudents ?.@$ NumMovies
>
> VotesTbl=: Groups ,/@(~.@[ ,."0 2 ({.,#)/.~/.) Votes
>
> VotesTbl=: (] \: {:"1) VotesTbl           NB. sort by votes across groups
>
> VotesTbl=: (#~ [: ~: 1&{"1) VotesTbl      NB. deduplicate movie entries
> MovieProgram=: ({."1 (3&{.)/. ]) VotesTbl NB. take top 3 choices for 
> each group
>
>
>
>
> On Wed, Aug 28, 2013 at 7:58 AM, Joe Bogner <[email protected]> wrote:
>
> > Thanks Brian - this looks like it solve it. I will study it to get a
> better
> > understanding of how to solve problems like this. Thanks for adding 
> > comments too. It makes the steps more clear.
> >
> >
> > On Tue, Aug 27, 2013 at 8:55 AM, Brian Schott 
> > <[email protected]
> > >wrote:
> >
> > > freqcount=: (\: {:"1)@(~. ,. #/.~) CT =: 100 picks =: CT ?.@$ 26 
> > > groups =: CT $ i. 3
> > > f =: groups <@freqcount/. picks         NB. freqcounts of picks
> > > g =:; (i. 3) ((|.&.|:)@>@]<@:,.[)"0 f   NB. appending group #s
> > > s =: \:~ g                              NB. sorting
> > > r =: (i.26) ((0,~])\:~@{~1&{"1@]i./ [)s NB. remove duplicates
> > > t =: |.({:"1@]</.])\:~&.(|.&.|:) r      NB. rearrange
> > > 3&{. each  t                            NB. first 3
> > >
> > > The above may be a solution, but is not well tested. Instead of 
> > > movie names, there are movie numbers.
> > >
> > >
> > >
> > >
> > >
> > >
> > > On Mon, Aug 26, 2013 at 11:22 PM, Joe Bogner <[email protected]>
> > wrote:
> > >
> > > > I solved this problem today at work in R using a loop and an
> > intermediate
> > > > data.table. I generalized it and then tried to solve it in J. I
> wasn't
> > > even
> > > > sure where to start.
> > > >
> > > > Let's say you have 100 students and 26 movies that need to be 
> > > > shared
> > by 3
> > > > groups of students. Each student has picked their favorite 
> > > > movie. I
> > need
> > > to
> > > > give 3 movies to each of the 3 groups based on the group's 
> > > > favorite choices. A movie can't be shared by groups.
> > > >
> > > >
> > > > movies=:(65 + i. 26) { a.
> > > >
> > > > CT=:100
> > > >
> > > >
> > > > NB. movie;student;age group
> > > >
> > > > students=:i.CT
> > > >
> > > > groups=:(CT $ (i.3))
> > > >
> > > > picks=: ((?. CT $ # movies) { movies);students;groups
> > > >
> > > >
> > > > NB. get an idea of what the most common choices are across all 
> > > > groups
> > > >
> > > > key=. > 0{"1 picks
> > > >
> > > > values=. CT $ 1
> > > >
> > > > sum=: +/
> > > >
> > > > counts=. (~.key) ; (i.~key) sum/. values
> > > >
> > > >
> > > > NB. sidenote how do I get this table format?
> > > >
> > > > NB. |-----|---|
> > > >
> > > > NB. |M | 1 |
> > > >
> > > > NB. |-----|---|
> > > >
> > > > NB. |W| 1 |
> > > >
> > > >
> > > >
> > > > Any advice on how to tackle this in J?
> > > >
> > > >
> > > > This is the solution in R
> > > >
> > > >
> > > > movies <- LETTERS
> > > >
> > > > CT <- 100
> > > >
> > > > students <- rep(0:(CT-1))
> > > >
> > > > groups <- sample(0:2,100,replace=T)
> > > >
> > > > picks <- data.table(data.frame(movie=sample(movies,100,
> > > > replace=T),student=students, group=groups))
> > > >
> > > >
> > > >
> > > > movie.groups <- picks[,.N,by=list(movie,group)]
> > > >
> > > > movie.groups[,Taken:=F]
> > > >
> > > >
> > > > ugroups <- unique(groups)
> > > >
> > > > for(i in 1:length(ugroups)) {
> > > >
> > > >     g<-ugroups[i]
> > > >
> > > >     top3 <- movie.groups[group==g & Taken==F,][order(-N)][1:3]
> > > >
> > > >
> > > >     setkey(top3,movie,group)
> > > >
> > > >     setkey(movie.groups,movie,group)
> > > >
> > > >     movie.groups[top3, ForGroup:=T,nomatch=0]
> > > >
> > > >
> > > >     setkey(top3, movie)
> > > >
> > > >     setkey(movie.groups,movie)
> > > >
> > > >     movie.groups[top3, Taken:=T,nomatch=0]
> > > >
> > > > }
> > > >
> > > >
> > > >
> > > > >movie.groups[ForGroup==T,list(movie,group)][order(group)]
> > > >
> > > >    movie group
> > > >
> > > > 1:     P     0
> > > >
> > > > 2:     T     0
> > > >
> > > > 3:     W     0
> > > >
> > > > 4:     F     1
> > > >
> > > > 5:     H     1
> > > >
> > > > 6:     N     1
> > > >
> > > > 7:     D     2
> > > >
> > > > 8:     E     2
> > > >
> > > > 9:     K     2
> > > >
> ----------------------------------------------------------------------
> > > > For information about J forums see
> http://www.jsoftware.com/forums.htm
> > > >
> > >
> > >
> > >
> > > --
> > > (B=) <-----my sig
> > > Brian Schott
> > > ------------------------------------------------------------------
> > > ---- For information about J forums see 
> > > http://www.jsoftware.com/forums.htm
> > >
> > --------------------------------------------------------------------
> > -- For information about J forums see 
> > http://www.jsoftware.com/forums.htm
> >
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
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