x0=: ,.(1+i.9)(([:":]),' X',(2":[),' =',(7#' '),~ 3":*)"0/2+i.4
x1=: ,.(1+i.9)(":@],' X',2&":@[,' =',(7#' '),~ 3":*)"0/2+i.4
x2=: ,.(1+i.9)(":@],' X',2&":@[,' =',(7#' '),~3":*)"0/2+i.4
x3=: ,.(1+i.9)(7|.8&":@],' X',2&":@[,' = ',2":*)"0/2+i.4
x4=: ,.(1+i.9)(7|.8&":@],' X ',":@[,' = ',2":*)"0/2+i.4
x5=: ,.(1+i.9)('_ X _ = __ '0 4 8 9}~1 1 2":,~,*)"0/2+i.4
x0 -: x1
1
x0 -: x2
1
x0 -: x3
1
x0 -: x4
1
x0 -: x5
1
But really, the whole exercise is biased; the real answer should be
+/~i.10
On Sat, Apr 26, 2014 at 4:25 PM, Don Guinn <[email protected]> wrote:
> A little shorter.
>
> ,.(1+i.9)(([:":]),' X',(2":[),' =',(7#' '),~ 3":*)"0/2+i.4
> 2 X 1 = 2 3 X 1 = 3 4 X 1 = 4 5 X 1 = 5
> 2 X 2 = 4 3 X 2 = 6 4 X 2 = 8 5 X 2 = 10
> 2 X 3 = 6 3 X 3 = 9 4 X 3 = 12 5 X 3 = 15
> 2 X 4 = 8 3 X 4 = 12 4 X 4 = 16 5 X 4 = 20
> 2 X 5 = 10 3 X 5 = 15 4 X 5 = 20 5 X 5 = 25
> 2 X 6 = 12 3 X 6 = 18 4 X 6 = 24 5 X 6 = 30
> 2 X 7 = 14 3 X 7 = 21 4 X 7 = 28 5 X 7 = 35
> 2 X 8 = 16 3 X 8 = 24 4 X 8 = 32 5 X 8 = 40
> 2 X 9 = 18 3 X 9 = 27 4 X 9 = 36 5 X 9 = 45
> ----------------------------------------------------------------------
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>
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