The negative in my algorithm was to indicate "working backwards". 

That is, if I want to end up with 2 cakes after bridge 7, during which you 
gained 1 and lost x/2, what must x be? Given that, what must you have had 
before bridge 6? And so on.

In other words, that expression was intended to be the J transliteration of "If 
you 'undo' 1+x%2 seven times, what do you start out with?".

-Dan

Please excuse typos; sent from a phone.

> On Jun 9, 2014, at 2:25 PM, Raul Miller <[email protected]> wrote:
> 
> For what it's worth, my algorithm came up with the same answer as Dan's for
> the 7 bridge 2 cake case, but comes up with a different answer for the 1
> bridge 3 case case:
>   +:@<:^:7: 2
> 
>   +:@<:^:1: 3
> 
> -- 
> Raul
> 
> 
> 
> 
>> On Mon, Jun 9, 2014 at 2:06 PM, greg heil <[email protected]> wrote:
>> 
>> Dan
>> 
>>> Rounding amongst Trolls is pretty peculiar;) Say you wanted to give
>> Granny 3 cakes and only had to cross one bridge ...  Your algorithm says
>> you only need start with 2.5 cakes! (Kinda unhygienic on the offspring's
>> part;-)
>> 
>> greg
>> ~krsnadas.org
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