I did not get the third set of two digits, but usually you start by assuming a mix of simple arithmetic and simple tricks.
-- Raul On Sat, Dec 13, 2014 at 8:42 PM, Joe Bogner <[email protected]> wrote: > Is there a method to solve a puzzle like this other than google or brute > forcing different combinations until something works for the 4 answers? > > I am genuinely curious. At best I typically can only recognize simple > patterns that use a few operations > On Dec 13, 2014 8:00 PM, "robert therriault" <[email protected]> wrote: > >> Hey Skip, >> >> I'm sure that there are more elegant ways but, here goes. >> >> fun=: 3 : 0 >> 'a b c'=. y >> (a*b*10000)+(a*c*100)+(a*b+c)-b >> ) >> fun 5 3 2 >> 151022 >> fun 9 2 4 >> 183652 >> fun 8 6 3 >> 482466 >> fun 5 4 5 >> 202541 >> fun 7 2 5 >> 143547 >> >> >> Cheers, bob >> >> >> On Dec 13, 2014, at 3:17 PM, Skip Cave <[email protected]> wrote: >> >> > Oops! printing mistake... >> > >> > fun 5 3 2 >> > 151022 >> > fun 9 2 4 >> > 183652 >> > >> > fun 8 6 3 >> > >> > 482466 >> > >> > fun 5 4 5 >> > >> > 202541 >> > >> > fun 7 2 5 >> > >> > ??? >> > >> > >> > >> > Skip Cave >> > Cave Consulting LLC >> > ---------------------------------------------------------------------- >> > For information about J forums see http://www.jsoftware.com/forums.htm >> >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
