Raul Miller <[email protected]> wrote: > > I'm going to _try_, but this hasn't been peer reviewed... But by
I think it's clear my proof was wrong, and so is the claim I was trying to prove. > Its pretty easy to come up with counter examples of this. I don't see this one. > Just find an irrational number whose expansion starts with 1 and then find > a conflicting rational (perhaps a ratio with 7 in the denominator). What does "conflicting rational" mean? There's only one rational that consists entirely of the leading zeros and first digit of the decimal expansion. If your irrational begins with 1 in the n-th digit and your radix is r, there's only one rational, and it's less than all of the irrationals beginning with those leading digits. > Raul -Wm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
