numtt=: 3 : '((,~ 0:) + (, 0:)) ^: (2^y) 1’ calculates, for the possible truth-tables of y variables a list of the those which have 0 1s, 1 1, 2 1s …..
e.g.
numtt 2
1 4 6 4 1
numtt just produces the appropriate row of Pascal’s Triangle.
It’s a trivial little verb, but I’m bothered by the fact that
I can’t see a way to make it tacit.
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