And to the chat
> So are you saying that Haskell's fold would not be suitable for
> something like this:
>
> M=: 20$'.'
> foldr=:1 :0
> :
> X=.<x
> Y=.y<@["u x
> >u&.>/Y,X
> )
>
> M 4 :'''*'' x} y' foldr 2 3 5 7 11 13 17 19
> ..**.*.*...*.*...*.*
>
> ?
>
No, e.g.
Prelude> foldl (\xs y -> (\(k,t) -> k ++ ('*':drop 1 t) ) $ splitAt y xs)
"..............." [2,5,7]
"..*..*.*......."
--
Met vriendelijke groet,
=@@i
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