Never mind, I figured it out... (365 ^ 30) %~ (!365x) % !365x - 30 0.293684
Skip On Tue, Feb 14, 2012 at 1:35 PM, Skip Cave <[email protected]> wrote: > I find it interesting that the TI calculator used by the Khan Academy > teacher solved the birthday problem by directly calculating the factorials > of 365 and 365-30. In J I had to reduce the fraction first because 365 > factorial shows as infinity in J , Can one solve Khan's birthday problem by > using extended arithmetic and not have to reduce the factorials? > > Skip > > > On Tue, Feb 14, 2012 at 1:03 PM, Skip Cave <[email protected]>wrote: > >> Here's a one-liner direct-execution answer for the Khan Academy birthday >> problem: >> (365 ^ 30) %~ */ _30 {. >: i. 365 >> 0.293684 >> >> ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
