... and then
;(,,~&.>/@:{.~&_2)^:(4)1;1 0
1 1 0 1 0 1 1 0 1 1 0 1 0 1 1 0 1 0 1 1 0 1 1 0 1 0 1 1 0 1 1 0
will run (much) faster.
On 25-06-12 10:53, I wrote:
> Thanks to the analysis of other people, see e.g.
> http://mrob.com/pub/math/seq-google-turing.html, it turns out that
> fibonacci is involved:
>
> Using these for generating the bits:
>
> ;bits=.([:;(-.`(,-.)@.])&.>)&.>^:(<12) <1
> 1 1 0 1 0 1 1 0 1 1 0 1 0 1 1 0 1 0 1 1 0 1 1 0 1 0 1 1 0 1 1 0 ...
>
> +/&> bits
> 1 1 2 3 5 8 13 21 34 55 89 144
>
>
>
>
>
>
> On 23-06-12 17:48, Devon McCormick wrote:
>> The link says it's spelling out "Google" but I believe that is
>> incorrect - it looks like it's just counting up in binary.
>>
>> On Sat, Jun 23, 2012 at 10:07 AM, Donna Y <[email protected]> wrote:
>>> Thanks for the link. I did not watch long enough. Yes it's the
>>> code breaker and not an implementation of his first proof. It
>>> simply spells out Google.
>>>
>>> As the video asks, imagine if Alan Turing could work on one of
>>> today's computers to expand on any of the many problems he was
>>> pursuing!
>>>
>>> Donna
>>> [email protected]
>>>
>>>
>>> On 2012-06-23, at 7:11 AM, Brian Schott <[email protected]> wrote:
>>>
>>>> Thanks.
>>>> Can the working model be saved somehow?
>>>> Btw, I found an interesting explanation at
>>>> http://news.cnet.com/8301-17852_3-57459126-71/googles-impossibly-clever-alan-turing-doodle/
>>>>
>>>>
>>>> That link suggests another purpose of the doodle.
>>>>
>>>> On Sat, Jun 23, 2012 at 1:26 AM, Donna Y <[email protected]> wrote:
>>>>> Its Alan Turing's birthday and that is the proof of the halting
>>>>> problem - see Church and Turing.
>>>>>
>>>>> Donna
>>>>> [email protected]
>>>>>
>>>>>
>>>> ----------------------------------------------------------------------
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>>>>
>>> ----------------------------------------------------------------------
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>>
>>
>
--
Met vriendelijke groet,
@@i = Arie Groeneveld
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