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In a message dated 11/27/2001 6:59:21 AM Eastern Standard Time, [EMAIL PROTECTED] writes: > Now you've got me curious. How can 37/10T be the SAME tooth count as > 41/11T? 37/10=3.70 while 41/11=3.72727272... I see nothing the same > except the procedure to calculate the ratio; but then I've been out of > school for some time. New math? > > Dale Must be. Looks like for the smaller 10 bolt ring gear only 37 teeth of a certain thickness would fit arount the circumference of the gear. So they went with a 37/10 combo to get the gear ratio they wanted. The larger 12 bolt ring gear having more circumference needs more teeth to fit hence the 41/11 combo. Different tooth count, same ratio, plus or minus a small fudge factor. Sound reasonable? --------------------- Kurt Ehrhardt ACES #1280 66 Malibu 66 SuperSport Enfield, CT ----------------------------------------------------- To Unsubscribe please visit www.chevelles.net/list.html To start a new topic, send mail to: [EMAIL PROTECTED]
