I had a question about the objectives and reasons of allowing un-specified key arguments in functions as soon as i want to have some key arguments. Take a look at the following case:
;;; The function (define (foo a #!key b) (list a b)) Now passing any number of key arguments in addition to b doesn't result in any error which makes the debugging of even some simple typing errors very difficult in a large code: (define (foo a #!key b) (list a b)) (foo 2) ; ===> (2 #f) (foo 2 #:b 3) ; ===> (2 3) (foo 2 #:b 3 #:c 4 #:d 5 #:e 6) ; ===> (2 3) without any errors! Why is this and what was the reasons of deciding this too much freedom? Regards, Amir _______________________________________________ Chicken-users mailing list Chicken-users@nongnu.org https://lists.nongnu.org/mailman/listinfo/chicken-users
